courses › Algebra

Systems of equations

level 24 course

Two equations, two unknowns, one answer.

Pen and paper is fine · no calculator needed why?

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the lesson

The idea, the techniques and a tip for each skill, right here. The Learn page adds worked examples for every skill and untimed practice.

Read the lesson · about 3 minutes

The idea

A system is two equations that share two unknowns, x and y. The answer is the one pair of values that makes both equations true at once.

The plan is always the same: get rid of one letter, solve for the other, then put that value back. Elimination adds or subtracts the equations. Substitution swaps y for what it equals. Give x first, then y.

Techniques

Add or subtract to eliminate

One letter has the same or opposite numbers in front of it in both equations.

  1. Opposite numbers in front, like y and −y: add the equations.
  2. The same number in front: subtract the second equation from the first.
  3. Solve for the letter that is left.
  4. Put it into the first equation to find the other letter.
worked example

Example: Solve the system 2x + y = 11 and 3x − y = 4. What is y?

  1. The y terms are opposites, so add: 5x = 15.
  2. So x = 3.
  3. Put x = 3 into the first: 6 + y = 11, so y = 5.

Answer: 5

Substitute for y

One equation already says y = something.

  1. Replace y in the other equation with what it equals, in brackets.
  2. Multiply out the bracket, every term inside it.
  3. Solve for x, then put x back into the y equation to get y.
worked example

Example: Solve the system y = x + 2 and 3x + 2y = 19. What is x?

  1. Substitute: 3x + 2(x + 2) = 19.
  2. Multiply out: 3x + 2x + 4 = 19, so 5x + 4 = 19.
  3. 5x = 15, so x = 3.

Answer: 3

Two items, one total

Two prices, a total count, and a total amount of money.

  1. Let a letter count the pricier item. The cheaper count is the total count minus it.
  2. Write one equation for the money, and multiply out the bracket.
  3. Solve. For the cheaper item, subtract from the total count.
worked example

Example: A bakery sells pies for $9 and tarts for $4. It sold 15 items for $85. How many tarts did it sell?

  1. Let p be pies, so 15 − p are tarts.
  2. 9p + 4(15 − p) = 85, so 5p + 60 = 85.
  3. So 5p = 25 and p = 5.
  4. Tarts: 15 − 5 = 10.

Answer: 10

Tips by skill

  • TipSolve by elimination: Opposite numbers in front of a letter? Add the equations. The same number? Subtract one from the other. Then solve and put back.
  • TipSolve by substitution: Put what y equals into the other equation, in brackets, and multiply every term inside. Solve for x, then find y.
  • TipTwo-item word problem: Let a letter be one item's count; the other count is the total minus it. Write one equation for the money.

Watch out for

  • Entering the right numbers in the wrong order. The answer is x first, then y.
  • Multiplying only the first term in the bracket: 2(x + 2) is 2x + 4.
  • Giving the count of the other item. Reread which one the question asks for.

skills · practice stats

From rounds of this course only: box, review and test-out answers are left out. Once a skill has 40 tries, it compares your first 20 tries with your last 20.

rest ladder

Win 3 of your last 4 rounds and the course rests. A win is 90% right, within 2× the round's par. Pass the review when it comes back and the next rest is longer.

  1. 1 day
  2. 3 days
  3. 7 days
  4. 14 days
  5. 30 days
  6. 60 days
  7. mastered · every 90 days

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