Systems of equations
Two equations, two unknowns, one answer.
Pen and paper is fine · no calculator needed why?
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the idea
A system is two equations that share two unknowns, x and y. The answer is the one pair of values that makes both equations true at once.
The plan is always the same: get rid of one letter, solve for the other, then put that value back. Elimination adds or subtracts the equations. Substitution swaps y for what it equals. Give x first, then y.
techniques
Add or subtract to eliminate
- Opposite numbers in front, like y and −y: add the equations.
- The same number in front: subtract the second equation from the first.
- Solve for the letter that is left.
- Put it into the first equation to find the other letter.
worked example
Solve the system 2x + y = 11 and 3x − y = 4. What is y?
- The y terms are opposites, so add: 5x = 15.
- So x = 3.
- Put x = 3 into the first: 6 + y = 11, so y = 5.
Answer: 5
Substitute for y
- Replace y in the other equation with what it equals, in brackets.
- Multiply out the bracket, every term inside it.
- Solve for x, then put x back into the y equation to get y.
worked example
Solve the system y = x + 2 and 3x + 2y = 19. What is x?
- Substitute: 3x + 2(x + 2) = 19.
- Multiply out: 3x + 2x + 4 = 19, so 5x + 4 = 19.
- 5x = 15, so x = 3.
Answer: 3
Two items, one total
- Let a letter count the pricier item. The cheaper count is the total count minus it.
- Write one equation for the money, and multiply out the bracket.
- Solve. For the cheaper item, subtract from the total count.
worked example
A bakery sells pies for $9 and tarts for $4. It sold 15 items for $85. How many tarts did it sell?
- Let p be pies, so 15 − p are tarts.
- 9p + 4(15 − p) = 85, so 5p + 60 = 85.
- So 5p = 25 and p = 5.
- Tarts: 15 − 5 = 10.
Answer: 10
watch out for
- Entering the right numbers in the wrong order. The answer is x first, then y.
- Multiplying only the first term in the bracket: 2(x + 2) is 2x + 4.
- Giving the count of the other item. Reread which one the question asks for.
practice
Solve by elimination
worked example
Solve the system: −x − 3y = −6 −x − 4y = −8 Enter x, y.
Answer: (0, 2)
- Subtract the second equation from the first: y = 2.
- Put y = 2 into the first equation: −x = −6 − (−6) = 0, so x = 0.
Solve by substitution
worked example
Solve the system: y = 2x + 4 3x + 5y = −19 Enter x, y.
Answer: (-3, -2)
- Substitute: 3x + 5(2x + 4) = −19.
- So 13x + 20 = −19, which gives 13x = −39.
- x = −3, and y = 2 × (−3) + 4 = −2.
Two-item word problem
worked example
A café sells large coffees for $5 and small coffees for $4. One morning it sold 58 coffees for $276. How many large coffees did it sell?
Answer: 44
- Let l be the number of large coffees, so 58 − l are small coffees: 5l + 4(58 − l) = 276.
- That gives l + 232 = 276, so l = 276 − 232 = 44.