learn › Trigonometry

Identities & equations

lesson · about 3 minutes

Use trig identities and solve trig equations.

Pen and paper is fine · no calculator needed why?

Opens at level 43. You're level 1. You can read and practice here now.

the idea

An identity is an equation that holds for every angle. The main one: the point (cos θ, sin θ) on the unit circle is 1 from the center, so sin² θ + cos² θ = 1. Know one value and the other follows, up to a sign the quadrant decides.

Two more: sin 2θ = 2 sin θ cos θ, and cos 2θ = cos² θ − sin² θ.

Sine and cosine repeat every 2π, tangent every π. That repeat length is the period. Squeezing the input, as in sin(2x), shortens it.

techniques

Use sin² + cos² = 1

You know sin θ or cos θ and the quadrant, and want the other.

  1. Square the value you know and take it from 1.
  2. Take the square root. That gives the size.
  3. Pick the sign from the quadrant: cosine is negative in II and III, sine in III and IV.
worked example

Example: cos θ = 5/13 and θ is in quadrant IV. What is sin θ? Give a fraction.

  1. sin² θ = 1 − 25/169 = 144/169.
  2. The square root gives a size of 12/13.
  3. Sine is negative in quadrant IV, so sin θ is −12/13.

Answer: −12/13

Period: divide by b

The period of y = sin(bx), cos(bx) or tan(bx).

  1. Sine and cosine: the period is 2π ÷ b. Tangent: π ÷ b.
  2. For k in kπ, divide 2 by b, or 1 by b for tangent.
worked example

Example: The period of y = cos(x/3) is kπ. What is k? Give a fraction or a whole number.

  1. x/3 means b is 1/3.
  2. Cosine: the period is 2π ÷ (1/3).
  3. k = 2 ÷ (1/3) = 6.

Answer: 6

Reference angle, two quadrants

Solving sin x or cos x equal to a special value, for 0° ≤ x < 360°.

  1. Find the reference angle r from the value's size, ignoring its sign.
  2. Find the two quadrants where the function has the value's sign.
  3. Quadrant I gives r, II gives 180° − r, III gives 180° + r, and IV gives 360° − r.
worked example

Example: Solve cos x = −1/2 for 0° ≤ x < 360°. What is the larger answer, in degrees?

  1. cos 60° = 1/2, so the reference angle is 60°.
  2. Cosine is negative in quadrants II and III.
  3. II: 180° − 60° = 120°. III: 180° + 60° = 240°.

Answer: 240

watch out for

practice

Sign in to try one

sin² + cos² = 1

worked example

sin θ = −20/29 and θ is in quadrant IV. What is cos θ? Give a fraction.

Answer: 21/29

  1. cos² θ = 1 − sin² θ = 1 − 400/841 = 441/841, so cos θ = ±21/29.
  2. Cosine is positive in quadrant IV, so cos θ = 21/29.

Period

worked example

The period of y = sin(2x) is kπ. What is k? Give a fraction or a whole number.

Answer: 1

  1. The period of sin(bx) is 2π ÷ b = 2π ÷ 2 = π, so k = 1.

Double angle

worked example

sin θ = −9/41 and cos θ = −40/41. What is cos 2θ? Give a fraction.

Answer: 1519/1681

  1. cos 2θ = cos² θ − sin² θ = 1600/1681 − 81/1681 = 1519/1681.

Solve a trig equation

worked example

Solve sin x = 1/2 for 0° ≤ x < 360°. Enter both answers in degrees, smaller first.

Answer: (30, 150)

  1. The reference angle is 30°, because sin 30° = 1/2.
  2. Sine is positive in quadrants I and II: 30° and 180° − 30° = 150°.

Sign in to start